(4x^2+32x)/20x

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Solution for (4x^2+32x)/20x equation: 


x in (-oo:+oo)

x*((4*x^2+32*x)/20) = 0

(x*(4*x^2+32*x))/20 = 0

4*x^2+32*x = 0

4*x*(x+8) = 0

x+8 = 0 // - 8

x = -8

4*x*(x+8) = 0

(4*x*x*(x+8))/20 = 0

( 4*x )

4*x = 0 // : 4

x = 0

( x+8 )

x+8 = 0 // - 8

x = -8

( x )

x = 0

x in { 0, -8, 0 }

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